اذا كان ا . ب حدثين متنافيين من فضاء عينة ف لتجربة عشوائية وكان :
ل ( ا ) = ل (ا ) , ل (ب ) = \frac{1}{2} ل ( ا ) فأوجد :
(i ) ل (ب )
( ii ) ل ( ا - ب )
( iii ) ل ( أ \cap ب )
(1) \because ل (ا) = ل (ا )
\therefore ل (ا ) = \frac{1}{2} ل ( ا ) = \frac{1}{4}
( ii ) ل ( ا - ب ) = ل ( ا ) - ل ( ا \cap ب )
= \frac{1}{2} - صفر = \frac{1}{2}
( iii ) ل ( ا \cap ب ) = 1 - ل ( ا \cup )
= 1 - [ ل (ا ) + ل (ب ) ]
= 1- [ \frac{1}{2} + \frac{1}{4} ]
= \frac{1}{4}