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Elsharkawy
منذ 8 سنوات
اجابة 1
مشاهدة
124
اجابة (1)
( i ) ل ( ز < 2 )
= ل ( صفر < ز < 2 )
= \frac{1}{2} [ د (صفر ) + د (2)] (2 - صفر )
= \frac{1}{8}< = \frac{1}{4} + \frac{1}{8}}
( ii ) ي ل (ك < ز < ك +2 ) = \frac{1}{2}
ى \frac{1}{2} [ د (ك ) +د (ك +2 ) ] (2) = \frac{1}{2}
ى \frac{ك+2}{6} = \frac{ك+4}{16} \frac{1}{2}
ى 2 ك +6 = 8
ى ك = 1