\because\ R=\frac{R1\times R2}{R1+R2} على التوازى

\therefore\ 2=\frac{R1\times R2}{R1+R2} 1

\because R1=R1+R2 على التوالى

\therefore9=R1+R2 2

\because R2=9-R1 3

بالتعريص من (2) فى (1) :

\therefore R12-9R1+18=0

​​​​​​​\therefore\left(9-R1\right)\left(R1-6\right)=0

​​​​​​​\therefore R1=\ \ \ \ \ \ \ \ \ \ \ \ او \ \ \ \ \ \ \ \ \ \ R1=6

​​​​​​​R2=6\ \ \ \ \ \ \ \ \ \ او \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ R2=3