مللى امبيير I2=I-I1=10-8=2

وحيث ان الفر ق فى الجهد لم يتغير :

\frac{R1}{R2}=\frac{V}{I1}\div\frac{V}{I2}=\frac{I2}{I1}=\frac{2}{8}

​​​​​​​=\frac{1}{4}

​​​​​​​\because\left(pe\right)1=\left(pc\right)2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \therefore\frac{R1A1}{e}=\frac{R2A2}{e}

​​​​​​​\therefore\frac{R1}{R2}=\frac{A2}{A1}=\frac{\pi r2\ 2}{\pi r1\ 2}=\frac{\left(r2\right)2}{\left(r1\right)2}

\frac{1​​​​​​​}{4}=\frac{\left(r2\right)2}{\left(r1\right)}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \therefore\ \frac{r2}{r1}=\frac{1}{2}​​​​​​​